A small post to let everybody know that I am alive 😉 .
Few weeks back, in office we were looking at one procedure which was supposed to do a lot but if executed it finished in a sec (or less 😉 ). I started looking into it and just opened the procedure and started scrolling to find that the last line of the very first cursor read:
where 1=2;
Wonderful !
You asked for it !!
1=2: A Proof using Beginning Algebra
* Step 1: Let a=b.
* Step 2: Then a² = ab,
* Step 3: a² + a² = a² + ab,
* Step 4: 2a² = a² + ab,
* Step 5: 2a² – 2ab = a² + ab – 2ab,
* Step 6: and 2a² – 2ab = a² – ab.
* Step 7: This can be written as 2(a² – ab) = 1(a² – ab),
* Step 8: and cancelling the (a² – ab) from both sides gives 1=2.
🙂
Oh man o man…ROFL…
Ek Mathematician ke hote huye aisa response kaise diya ja sakta hai 🙂
2(a^2-ab)=1(a^2-ab) =>2=1 iff a^2-ab 0
ha ha 🙂
waise ye kis procedure ki bat kar raha hai Sidhu,mujhe bhi pata lage !
Oh my God 😛