A small post to let everybody know that I am alive ;) .

Few weeks back, in office we were looking at one procedure which was supposed to do a lot but if executed it finished in a sec (or less ;) ). I started looking into it and just opened the procedure and started scrolling to find that the last line of the very first cursor read:

where 1=2;

Wonderful !

Comments

Comment by Vaibhav Garg on 2008-12-08 13:12:08 +0530

**You asked for it !!

1=2: A Proof using Beginning Algebra

  • Step 1: Let a=b.
  • Step 2: Then a² = ab,
  • Step 3: a² + a² = a² + ab,
  • Step 4: 2a² = a² + ab,
  • Step 5: 2a² – 2ab = a² + ab – 2ab,
  • Step 6: and 2a² – 2ab = a² – ab.
  • Step 7: This can be written as 2(a² – ab) = 1(a² – ab),
  • Step 8: and cancelling the (a² – ab) from both sides gives 1=2.

🙂

Comment by Sidhu on 2008-12-09 20:11:33 +0530

Oh man o man…ROFL…

Comment by Monika Sharma on 2008-12-29 02:36:47 +0530

Ek Mathematician ke hote huye aisa response kaise diya ja sakta hai 🙂
2(a^2-ab)=1(a^2-ab) =>2=1 iff a^2-ab 0
ha ha 🙂
waise ye kis procedure ki bat kar raha hai Sidhu,mujhe bhi pata lage !

Comment by Sidhu on 2009-01-31 21:13:42 +0530

Oh my God 😛